Program to find two largest numbers using Python

nums = [10, 90, 80, 60, 50]
maxone = 0
maxtwo = 0
for x in nums:
if(maxone < x):
maxtwo = maxone
maxone = x

elif (maxtwo < x):
maxtwo = x

print "First two largest numbers"
print "First largest number:", maxone
print "First largest number:", maxtwo


output:

First two largest numbers
First largest number: 90
First largest number: 80

Sorting a list with out sort/sorted functions - Python

lst = [1,0,4,5,6,7,8,0,0,0]

print(lst)
cou = len(lst)
for i in range(cou):
    for j in range(1, cou-i):
       #descending
        """if lst[j] > lst[j-1]:
            (lst[j-1], lst[j]) = (lst[j], lst[j-1])"""
        #ascending  
        if lst[j] < lst[j-1]:
            (lst[j-1], lst[j]) = (lst[j], lst[j-1])
print(lst)

Selenium script to get list of values

//code to get list of values

package Ecomm_selenium;

import java.util.List;

import org.openqa.selenium.By;

import org.openqa.selenium.WebDriver;

import org.openqa.selenium.WebElement;

import org.openqa.selenium.firefox.FirefoxDriver;

//Getting list of webElements

public class Login {

                /**

                * @param args

                */

                public static void main(String[] args) {

                                // TODO Auto-generated method stub

                               

                                String site = "http://www.flipkart.com/";

                    String paths = ".//*[@id='fk-mainbody-id']/div/div[2]";                            

                    //String

                               

                                WebDriver d = new FirefoxDriver();

                                d.get(site);

                                List<WebElement> colu_vals = d.findElements(By.className("goquickly-list"));

                                java.util.Iterator<WebElement> i = colu_vals.iterator();

                                while(i.hasNext())

                                {

                                                WebElement value = i.next();

                                                System.out.println(value.getText());

                                               

                                }

                               

                               

                }

}