Print elements of linkedlist - Golang

 This is 3rd post on linked list. For previous posts, pls check the links below:

https://sreesindhusruthi.blogspot.com/2021/07/create-single-linked-list-in-golang.html

https://sreesindhusruthi.blogspot.com/2021/07/length-of-linkedlist-implementation-in.html

Writing print function for linked list to print elements.

The function name is Print and elements data is available in Node.data .

Step1: Check if linked list is empty. If empty print "NULL"

Step2: Print Node.data and update head to next Node in the linkedlist.

The function code is :

func (ll *LinkedList) Print() {
   if ll.head == nil{
      fmt.Print("NULL")
      return
   }
   //No Intermediate variable is used so we are traversing on
   //the actual object created and it's references gets updated on updating ll.head.
   for ll.head != nil {
      fmt.Printf("%+v -->",ll.head.data)
      ll.head = ll.head.next
      ll.Print()
   }
}

Complete code: